There is an alternative explanation:
Several questions has to be answered if the above is to be true. What is happening to the energy emitted when the dualet is in the negative space? Suppose object other than earth but in the same line moves towards to the dualet in such a way that ducat's moving out velocity is less than c. Therefore is in positive space and should be visible to that object and not to earth? This is a baffling proposition. The photons that might reach earth are kept without traveling and the photons that can reach the object will be emitted. Therefore the earth and the object are directly inserting an influence on the dualet in emitting the electromagnetic radiation.
Another thing that can be assumed is what is emitted is not pure electromagnetic waves. It is something other than electromagnetic waves say dark energy. But by the actions of the observer converted to electromagnetic waves. Action of the observer is it's movement relative to these dark energy.
A light source will not emit dark energy. If we start moving grater than c relative to the source the energy will become dark energy and the source will become dark matter. Velocity of dark energy v is some v > c. So dark energy will have velocities that makes it travel across. Whenever some object moves in such a way that its velocity relative to dark energy is c it will become visible. Then this object will be traveling at velocity v < c relative to the source of dark energy.
Dark energy do not have a velocity component. It will originate from any source emitting energy. Visibility of energy will depend on the velocity of the observer relative to the source. If the velocity is greater then c the energy is will be dark energy and the source a dark object. If velocity is less then c energy will be electromagnetic radiation with velocity c.
Set of rules behavior
- Suppose a photon is emitted by an object that is not in dark, but by the time it reaches the observer the object accelerates and become dark matter, how will the observer see the photon? He will not see the photon. Because at the time of observance, the originator is in the dark. If we assume otherwise we need to think of some ether where the photon travels. This is contradicted by the constant speed of light in all reference frames.
- The energy is conserved and only a shift from dark to light happens.
- Observability of a EM radiation will depend on the relative velocity between the emitter and observer exactly at the time of observance. If it is greater then c the radiation wisps past the observer and will never be able to observe it. Another observer more distant in the same line of sight if his relative velocity is less than c will observer it. The radiation will go through the first observer as if it is nonexistent. The radiation for the first observer will be dark energy. The second observer will see the fist observer if relative velocity is less than c. But will also see radiation coming through the first observer as if it is nonexistent.
- There will be a violation of locality principal. Spooky action at distance will become true and very common.
- If the velocity between the observer and the emitter is less than c, everything will behave according to current classical laws, not special relativistic laws.
- Here no ether is assumed and EM radiation velocity is also assumed to be the constant c irrespective of observer movements. But the assumption of the velocity limit of c as predicted in Special Relativity is dropped.
- A message can be sent by the emitter to the observer, when the emitter moves in an out of dark space. However the message will be traveling at the velocity of light. Above example of pulsars is such an event. In the visible window the observer will see EM radiation. Hoover, at all times dark energy will be imitated. In the window of visibility it is converted to EM radiation.
- Space can consist by large amount of dark energy that zip past us with out any knowledge. Dark matter will be the objects that moves out from us at velocities greater than c.
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