Tuesday, November 17, 2015

Special Relativity Flawed

It can be proved that Special Relativity Flawed.
Take the basic example of a photon emitted in a frame:
Frame example

Moving Observer
a frame AB moves at a velocity v, emits a photon -- photon is more accurate than a light signal. After time t the photon arrives at D since the frame has now moved to CD. All this activity is relative to an observer standing on the frame AB/CD, that moves at velocity v with the frame.

With respect to the observer on the frame
We can safely state r = c * t where c is the velocity of light (r - size of the frame). Since light travels at velocity c for any observer -- Michelson Morly Experiment.

With respect of the stationary observer standing outside the frame
Here again velocity of light is the constant c. Light photon will be moving from point at Aο and reach point Bο after time tο. Though at the same time, point B will start moving to D, this needs to be disregarded, since point B or D has no bearing or relevance to the stationary observer. This important phenomena, is missed by Special Relativity activists, they assume that, light coming from point Aο, is going to point D, moving at velocity c with respect of the stationary observer.

The mistake
This is wrong. Light travels at constant velocity c to the stationary observer, but not in respect to moving point B--as said earlier, point B is irrelevant to stationary observer. The Special Relativists argue that according to the stationary observer light will travel from A with velocity c, while point B of the frame  will move to point D, independent of the in coming light photon. Therefore the light photon will have to travel additionally a distance s to reach D. This is an unnecessary assumption. While traveling observer can consider light travel from A to D the stationary observer sees the same photon -- or with quantum theory different photon emitted almost at same time-- traveling from point A to B.

This mistaken argument results, either velocity of light should be c+v or frame AB need to contract or time need to dilate. But since velocity of light is constant the frame should contract and time need to dilate. Therefore moving frames contract. And time tο for stationary observer will be different from time t of the moving observer.
(It may look strange but putting the arguments to language is really difficult)

Mirror Example
A frame consisting with two parallel mirrors that has a light source directed up--this is a light clock, will be moving forward at velocity v




Scenario 1  c & d - invariant and t -variant (The normal accepted principal of Special Relativity)
2d = c tο ---------------(1)
         __________
d = √c²t²/4 – v²t²/4
            ______
= tc/2 1-v²/c² ---------- (2)
                     _____
c tο/2 = tc/21-v²/c²
          ______
tο = t 1-v²/c²      ------ (accepted time dilation formula in Special Relativity)


 Scenario 2  t & d - invariant and c -variant (velocities greater than c exist Principal )

2d = cο t ---------------(1)
         __________
d = √c²t²/4 – v²t²/4
            ______
= tc/2 1-v²/c² ---------- (2)
                     _____
cο t/2 = tc/21-v²/c²
            ____
  cο c²-v²
  cο²  c²-v²
        _______
c = cο²  + v²       -----------(velocities greater than c exist Principal )


 Scenario 3  t & c - invariant and d -variant (Space Contraction Principal)

2dο = c t ---------------(1)
         __________
d = √c²t²/4 – v²t²/4
            ______
= tc/2 1-v²/c² ---------- (2)
                        _____
d = (2dο/c)c/21-v²/c²
             ______
 d = dο 1-v²/c²    ------ (Space Contraction Principal)
 
Scenario 1 accepts Special Relativity time dilation formula. It assumes that velocity of light is the same to all observers and goes beyond by assuming the stationary observer will not calculate c - v as the photon approach velocity towards mirror(photon moving in at c  mirror moving out at v)  but just as c. The stationary observer thinking  that, the photon moves towards the mirror at c. This is how the formula             
         __________
d = √c²t²/4 – v²t²/4   is derived. 

There is a problem with Scenario 1 because it leads to multiple paradoxes like twin paradox, grandfather paradox, ladder paradox, train on a bridge or tunnel paradox etc. Though some of these are said to be avoided by stating the shift from initial to non-initial frames looks like callous disregard to these paradoxes.
You get paradoxes because something is wrong or you cannot explain something. Then you need to give careful considerations to the assumption you have made and try to find the lapses. Another major defect of this theory is melding with time. The concept of time is one of the least understood. However, special relativity has made drastic changes to the concept of time. For instance we use phrases like "trillionth of a second after big bang" commonly. These phrases brings out pure absurdity because where was such a clock to measure time at that epoch. This shows how flimsy our understanding of time is.

Scenario 2  accepts that though light will have constant velocity with respect to any observer, velocities higher than light exist. Take for example the Frame Example above, a stationary observer will see that photon emitted at point A moves towards point D at c. But the stationary observer will also see that point D is moving at v. Therefore the stationary observer should say that photon moves towards D at c-v. And if the frame moves the other way c+v. Therefore velocities greater than c exist.

However, the two speed theory may run to problems if we consider a hole in the mirror allows light to fall on a screen of the stationary observer and how it is possible to have the same light photon or very near two photons to have two velocities of light. The observer moving with mirrors will see velocity c while the stationary observer will see velocity c²  + v²

Still, higher than c velocities may explain, quasars with z > 4 traveling at velocity greater than 4c.

Scenario 3  may give us very interesting explanations for hitherto unexplained phenomena.Here the distance between the mirrors will contract. This contraction will compensate the longer distance that the light beam need to travel when the mirror moves. The practical implication will be when the photon moves the space around it will contract.

We may be able to construct a new transformation (space contraction transformation) by the following formulas:                                                ______                                           _____
               x = xο                             y = yο 1-v²/c²                               z  = zο 1-v²/c²

These formulas will give out further interesting explanations to other phenomena. For instance say v > c then the space will become negative space. Whatever inside this space will be invisible like black holes. But this whatever inside can interact in other ways other than electromagnetic waves. For instance gravitation

When we observe a galaxy in the sky we know it's velocity by the red shift. Then we should know that the size will appear smaller depending on the red shift. Dark Mater and Dark Energy may be the result that these entities are inside a negative space created by it moving faster than light towards us.

These concepts will create a host of new hypothesis that can be tested by scientists in future to give us better explanation of what is around us.

see also twin paradox  and Observer in Einstein's Train thought experiment

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